B4 2.0/1.6 differences

missfire · 24-06-17, 10:08 AM

Hello,

I'm currently looking at reviving a crap box 80! I can't be arsed changing rings which is what I suspect it needs and can't find a 1.6 block to stick into it, only 2.0 ones. I was wondering if anyone knows if the loom is vastly different if I stuck in a 2.0 block/engine and ecu?

Inspired recently by this masterpiece -

https://m.youtube.com/watch?v=Lv4yoQKJ12s

ian20v · 24-06-17, 11:18 AM

Quote:

Originally Posted by missfire

Hello,

Inspired recently by this masterpiece -

https://m.youtube.com/watch?v=Lv4yoQKJ12s

I've had a few.

John. · 24-06-17, 04:01 PM

I would like to think that if you just swapped the block, then initially the engine would run lean as it'd draw more air than what the ECU would expect. But as it has a lambda sensor and runs a closed loop system then it should adjust the time the injector(s?) is open for to maintain the correct air/fuel (stoichiometric/lambda) ratio.

If you have a block, and time is your own......I'd do it!

If it doesn't work, disregard the above!

missfire · 24-06-17, 04:43 PM

Suppose I better find out what the engine code is first.

it looks identical to the 2.0. four injectors, will do some goooling.

24-06-17, 04:01 PM	#3
John. 4 ring whore! Classic Audi Club Member Join Date: Mar 2011 Location: Scottish Borders. Posts: 7,540	I would like to think that if you just swapped the block, then initially the engine would run lean as it'd draw more air than what the ECU would expect. But as it has a lambda sensor and runs a closed loop system then it should adjust the time the injector(s?) is open for to maintain the correct air/fuel (stoichiometric/lambda) ratio. If you have a block, and time is your own......I'd do it! If it doesn't work, disregard the above!

24-06-17, 04:43 PM	#4
missfire making wooden things Classic Audi Club Member Join Date: Dec 2009 Location: cow land Posts: 8,156	Suppose I better find out what the engine code is first. it looks identical to the 2.0. four injectors, will do some goooling.